Base | Representation |
---|---|
bin | 1001111110001110100… |
… | …00001101101001000111 |
3 | 1012202102112122101022021 |
4 | 10333013100031221013 |
5 | 21103214201120201 |
6 | 421224210344011 |
7 | 33520033162054 |
oct | 4770720155107 |
9 | 1182375571267 |
10 | 342645332551 |
11 | 1223513a2895 |
12 | 564a728b007 |
13 | 26407c66bb2 |
14 | 12826b9202b |
15 | 8da652cea1 |
hex | 4fc740da47 |
342645332551 has 2 divisors, whose sum is σ = 342645332552. Its totient is φ = 342645332550.
The previous prime is 342645332521. The next prime is 342645332629. The reversal of 342645332551 is 155233546243.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-342645332551 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 342645332498 and 342645332507.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (342645332501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171322666275 + 171322666276.
It is an arithmetic number, because the mean of its divisors is an integer number (171322666276).
Almost surely, 2342645332551 is an apocalyptic number.
342645332551 is a deficient number, since it is larger than the sum of its proper divisors (1).
342645332551 is an equidigital number, since it uses as much as digits as its factorization.
342645332551 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1296000, while the sum is 43.
Adding to 342645332551 its reverse (155233546243), we get a palindrome (497878878794).
The spelling of 342645332551 in words is "three hundred forty-two billion, six hundred forty-five million, three hundred thirty-two thousand, five hundred fifty-one".
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