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34269503875141 is a prime number
BaseRepresentation
bin1111100101010111111011…
…00110101110100001000101
311111100010120122110211102111
413302223331212232201011
513442432420443001031
6200515105344341021
710134614152501663
oct762537546564105
9144303518424374
1034269503875141
11aa12684595a47
123a157ab614771
1316177a5c75192
1486691d559c33
153e6665eb91b1
hex1f2afd9ae845

34269503875141 has 2 divisors, whose sum is σ = 34269503875142. Its totient is φ = 34269503875140.

The previous prime is 34269503875067. The next prime is 34269503875153. The reversal of 34269503875141 is 14157830596243.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29470468826241 + 4799035048900 = 5428671^2 + 2190670^2 .

It is a cyclic number.

It is not a de Polignac number, because 34269503875141 - 229 = 34268967004229 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34269503875241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17134751937570 + 17134751937571.

It is an arithmetic number, because the mean of its divisors is an integer number (17134751937571).

It is a 1-persistent number, because it is pandigital, but 2⋅34269503875141 = 68539007750282 is not.

Almost surely, 234269503875141 is an apocalyptic number.

It is an amenable number.

34269503875141 is a deficient number, since it is larger than the sum of its proper divisors (1).

34269503875141 is an equidigital number, since it uses as much as digits as its factorization.

34269503875141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21772800, while the sum is 58.

The spelling of 34269503875141 in words is "thirty-four trillion, two hundred sixty-nine billion, five hundred three million, eight hundred seventy-five thousand, one hundred forty-one".