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3428688248471 is a prime number
BaseRepresentation
bin110001111001001101101…
…111101011111010010111
3110010210001011211200000002
4301321031233223322113
5422133423142422341
611143041224241515
7502500043150343
oct61711557537227
913123034750002
103428688248471
11110210a148832
1247460491029b
131bb4298424a5
14bbd41204623
155e2c4a0429b
hex31e4dbebe97

3428688248471 has 2 divisors, whose sum is σ = 3428688248472. Its totient is φ = 3428688248470.

The previous prime is 3428688248411. The next prime is 3428688248477. The reversal of 3428688248471 is 1748428868243.

It is a strong prime.

It is an emirp because it is prime and its reverse (1748428868243) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3428688248471 - 218 = 3428687986327 is a prime.

It is a super-3 number, since 3×34286882484713 (a number of 39 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3428688248398 and 3428688248407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3428688248477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1714344124235 + 1714344124236.

It is an arithmetic number, because the mean of its divisors is an integer number (1714344124236).

Almost surely, 23428688248471 is an apocalyptic number.

3428688248471 is a deficient number, since it is larger than the sum of its proper divisors (1).

3428688248471 is an equidigital number, since it uses as much as digits as its factorization.

3428688248471 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 132120576, while the sum is 65.

The spelling of 3428688248471 in words is "three trillion, four hundred twenty-eight billion, six hundred eighty-eight million, two hundred forty-eight thousand, four hundred seventy-one".