Base | Representation |
---|---|
bin | 1001111110101100100… |
… | …10001011100111110011 |
3 | 1012210002010011011100101 |
4 | 10333112102023213303 |
5 | 21104223230204203 |
6 | 421305215333231 |
7 | 33526214501005 |
oct | 4772622134763 |
9 | 1183063134311 |
10 | 342897506803 |
11 | 122470781065 |
12 | 56557821217 |
13 | 2644828b127 |
14 | 1284c476375 |
15 | 8dbd74141d |
hex | 4fd648b9f3 |
342897506803 has 4 divisors (see below), whose sum is σ = 342939728088. Its totient is φ = 342855285520.
The previous prime is 342897506797. The next prime is 342897506827. The reversal of 342897506803 is 308605798243.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 342897506803 - 29 = 342897506291 is a prime.
It is a super-3 number, since 3×3428975068033 (a number of 36 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (342897506873) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21098458 + ... + 21114703.
It is an arithmetic number, because the mean of its divisors is an integer number (85734932022).
Almost surely, 2342897506803 is an apocalyptic number.
342897506803 is a deficient number, since it is larger than the sum of its proper divisors (42221285).
342897506803 is an equidigital number, since it uses as much as digits as its factorization.
342897506803 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42221284.
The product of its (nonzero) digits is 8709120, while the sum is 55.
The spelling of 342897506803 in words is "three hundred forty-two billion, eight hundred ninety-seven million, five hundred six thousand, eight hundred three".
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