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3429111673453 is a prime number
BaseRepresentation
bin110001111001100110111…
…110111011001001101101
3110010211010200120212212211
4301321212332323021231
5422140310042022303
611143151231530421
7502513404204454
oct61714676731155
913124120525784
103429111673453
111102307163234
12474702689a11
131bb49649610b
14bbd81545b9b
155e2ebc9366d
hex31e66fbb26d

3429111673453 has 2 divisors, whose sum is σ = 3429111673454. Its totient is φ = 3429111673452.

The previous prime is 3429111673417. The next prime is 3429111673607. The reversal of 3429111673453 is 3543761119243.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2158040326729 + 1271071346724 = 1469027^2 + 1127418^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3429111673453 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3429111673397 and 3429111673406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3429111613453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1714555836726 + 1714555836727.

It is an arithmetic number, because the mean of its divisors is an integer number (1714555836727).

Almost surely, 23429111673453 is an apocalyptic number.

It is an amenable number.

3429111673453 is a deficient number, since it is larger than the sum of its proper divisors (1).

3429111673453 is an equidigital number, since it uses as much as digits as its factorization.

3429111673453 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1632960, while the sum is 49.

The spelling of 3429111673453 in words is "three trillion, four hundred twenty-nine billion, one hundred eleven million, six hundred seventy-three thousand, four hundred fifty-three".