Base | Representation |
---|---|
bin | 110001111010101000101… |
… | …100001001010111101101 |
3 | 110010220222111220021101121 |
4 | 301322220230021113231 |
5 | 422200034244002323 |
6 | 11143452451340541 |
7 | 502552621215232 |
oct | 61725054112755 |
9 | 13126874807347 |
10 | 3430214047213 |
11 | 1102822449a28 |
12 | 47496b8b1751 |
13 | 1bb610998395 |
14 | bc047b01789 |
15 | 5e363947a5d |
hex | 31ea8b095ed |
3430214047213 has 4 divisors (see below), whose sum is σ = 3430222186048. Its totient is φ = 3430205908380.
The previous prime is 3430214047133. The next prime is 3430214047237. The reversal of 3430214047213 is 3127404120343.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3430214047213 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3430214047613) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3400581 + ... + 4292362.
It is an arithmetic number, because the mean of its divisors is an integer number (857555546512).
Almost surely, 23430214047213 is an apocalyptic number.
It is an amenable number.
3430214047213 is a deficient number, since it is larger than the sum of its proper divisors (8138835).
3430214047213 is an equidigital number, since it uses as much as digits as its factorization.
3430214047213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8138834.
The product of its (nonzero) digits is 48384, while the sum is 34.
Adding to 3430214047213 its reverse (3127404120343), we get a palindrome (6557618167556).
The spelling of 3430214047213 in words is "three trillion, four hundred thirty billion, two hundred fourteen million, forty-seven thousand, two hundred thirteen".
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