Base | Representation |
---|---|
bin | 1001111111000101111… |
… | …00111011101100010101 |
3 | 1012210121221001222112220 |
4 | 10333202330323230111 |
5 | 21110142132242331 |
6 | 421342250532553 |
7 | 33534405136215 |
oct | 4774274735425 |
9 | 1183557058486 |
10 | 343110040341 |
11 | 12256a744712 |
12 | 565b6a37159 |
13 | 26480313213 |
14 | 1286c79c245 |
15 | 8dd2224296 |
hex | 4fe2f3bb15 |
343110040341 has 4 divisors (see below), whose sum is σ = 457480053792. Its totient is φ = 228740026892.
The previous prime is 343110040331. The next prime is 343110040349. The reversal of 343110040341 is 143040011343.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 343110040341 - 26 = 343110040277 is a prime.
It is a super-4 number, since 4×3431100403414 (a number of 47 digits) contains 4444 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (343110040349) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57185006721 + ... + 57185006726.
It is an arithmetic number, because the mean of its divisors is an integer number (114370013448).
Almost surely, 2343110040341 is an apocalyptic number.
It is an amenable number.
343110040341 is a deficient number, since it is larger than the sum of its proper divisors (114370013451).
343110040341 is a wasteful number, since it uses less digits than its factorization.
343110040341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 114370013450.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 343110040341 its reverse (143040011343), we get a palindrome (486150051684).
The spelling of 343110040341 in words is "three hundred forty-three billion, one hundred ten million, forty thousand, three hundred forty-one".
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