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343125484373909 is a prime number
BaseRepresentation
bin100111000000100100010000…
…0100111000000011110010101
31122222220110211222010112202202
41032001020200213000132111
5324433231442444431114
63213433401005414245
7132162666241423466
oct11601104047003625
91588813758115682
10343125484373909
119a36a778736706
123259802656a385
131195c7959b8ba3
1460a350d69ad6d
1529a07344a9cde
hex13812209c0795

343125484373909 has 2 divisors, whose sum is σ = 343125484373910. Its totient is φ = 343125484373908.

The previous prime is 343125484373873. The next prime is 343125484373923. The reversal of 343125484373909 is 909373484521343.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 272914860418225 + 70210623955684 = 16520135^2 + 8379178^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-343125484373909 is a prime.

It is a super-3 number, since 3×3431254843739093 (a number of 45 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (343125484373509) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171562742186954 + 171562742186955.

It is an arithmetic number, because the mean of its divisors is an integer number (171562742186955).

Almost surely, 2343125484373909 is an apocalyptic number.

It is an amenable number.

343125484373909 is a deficient number, since it is larger than the sum of its proper divisors (1).

343125484373909 is an equidigital number, since it uses as much as digits as its factorization.

343125484373909 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 235146240, while the sum is 65.

The spelling of 343125484373909 in words is "three hundred forty-three trillion, one hundred twenty-five billion, four hundred eighty-four million, three hundred seventy-three thousand, nine hundred nine".