343312110403303 has 4 divisors (see below), whose sum is σ = 344028837147840. Its totient is φ = 342595383658768.

The previous prime is 343312110403259. The next prime is 343312110403309. The reversal of 343312110403303 is 303304011213343.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-343312110403303 is a prime.

It is a super-2 number, since 2×343312110403303² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (343312110403309) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 358363371550 + ... + 358363372507.

It is an arithmetic number, because the mean of its divisors is an integer number (86007209286960).

Almost surely, 2^{343312110403303} is an apocalyptic number.

343312110403303 is a deficient number, since it is larger than the sum of its proper divisors (716726744537).

343312110403303 is an equidigital number, since it uses as much as digits as its factorization.

343312110403303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 716726744536.

The product of its (nonzero) digits is 23328, while the sum is 31.

Adding to 343312110403303 its reverse (303304011213343), we get a palindrome (646616121616646).

The spelling of 343312110403303 in words is "three hundred forty-three trillion, three hundred twelve billion, one hundred ten million, four hundred three thousand, three hundred three".