Search a number
-
+
343313001401 is a prime number
BaseRepresentation
bin1001111111011110000…
…11001010101110111001
31012211011001222110210012
410333233003022232321
521111101112021101
6421414341031305
733542421235346
oct4775703125671
91184131873705
10343313001401
1112266426a327
12566529b5535
13264b3396216
141288b7117cd
158de4e65bbb
hex4fef0cabb9

343313001401 has 2 divisors, whose sum is σ = 343313001402. Its totient is φ = 343313001400.

The previous prime is 343313001391. The next prime is 343313001407. The reversal of 343313001401 is 104100313343.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 329682672400 + 13630329001 = 574180^2 + 116749^2 .

It is a cyclic number.

It is not a de Polignac number, because 343313001401 - 222 = 343308807097 is a prime.

It is not a weakly prime, because it can be changed into another prime (343313001407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171656500700 + 171656500701.

It is an arithmetic number, because the mean of its divisors is an integer number (171656500701).

Almost surely, 2343313001401 is an apocalyptic number.

It is an amenable number.

343313001401 is a deficient number, since it is larger than the sum of its proper divisors (1).

343313001401 is an equidigital number, since it uses as much as digits as its factorization.

343313001401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 343313001401 its reverse (104100313343), we get a palindrome (447413314744).

The spelling of 343313001401 in words is "three hundred forty-three billion, three hundred thirteen million, one thousand, four hundred one".