Base | Representation |
---|---|
bin | 1001111111100000100… |
… | …00101000111001100011 |
3 | 1012211012111012021000102 |
4 | 10333300100220321203 |
5 | 21111121311410201 |
6 | 421420344213015 |
7 | 33543055661264 |
oct | 4776020507143 |
9 | 1184174167012 |
10 | 343333310051 |
11 | 122674780536 |
12 | 5665976a16b |
13 | 264b7656c84 |
14 | 128902ba96b |
15 | 8de6b2826b |
hex | 4ff0428e63 |
343333310051 has 2 divisors, whose sum is σ = 343333310052. Its totient is φ = 343333310050.
The previous prime is 343333310039. The next prime is 343333310057. The reversal of 343333310051 is 150013333343.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 343333310051 - 222 = 343329115747 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 343333309996 and 343333310023.
It is not a weakly prime, because it can be changed into another prime (343333310057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171666655025 + 171666655026.
It is an arithmetic number, because the mean of its divisors is an integer number (171666655026).
Almost surely, 2343333310051 is an apocalyptic number.
343333310051 is a deficient number, since it is larger than the sum of its proper divisors (1).
343333310051 is an equidigital number, since it uses as much as digits as its factorization.
343333310051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14580, while the sum is 29.
Adding to 343333310051 its reverse (150013333343), we get a palindrome (493346643394).
The spelling of 343333310051 in words is "three hundred forty-three billion, three hundred thirty-three million, three hundred ten thousand, fifty-one".
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