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34333341401 is a prime number
BaseRepresentation
bin11111111110011011…
…010011011011011001
310021121202020110021002
4133332123103123121
51030303313411101
623434510354345
72323545405152
oct377633233331
9107552213232
1034333341401
1113619304617
1267a21bb9b5
133312089438
141939b70929
15d5e296d6b
hex7fe6d36d9

34333341401 has 2 divisors, whose sum is σ = 34333341402. Its totient is φ = 34333341400.

The previous prime is 34333341397. The next prime is 34333341403. The reversal of 34333341401 is 10414333343.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 34188379801 + 144961600 = 184901^2 + 12040^2 .

It is a cyclic number.

It is not a de Polignac number, because 34333341401 - 22 = 34333341397 is a prime.

Together with 34333341403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (34333341403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17166670700 + 17166670701.

It is an arithmetic number, because the mean of its divisors is an integer number (17166670701).

Almost surely, 234333341401 is an apocalyptic number.

It is an amenable number.

34333341401 is a deficient number, since it is larger than the sum of its proper divisors (1).

34333341401 is an equidigital number, since it uses as much as digits as its factorization.

34333341401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 34333341401 its reverse (10414333343), we get a palindrome (44747674744).

The spelling of 34333341401 in words is "thirty-four billion, three hundred thirty-three million, three hundred forty-one thousand, four hundred one".