3433434113 has 4 divisors (see below), whose sum is σ = 3445829460. Its totient is φ = 3421038768.

The previous prime is 3433434107. The next prime is 3433434127. The reversal of 3433434113 is 3114343343.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3114343343 = 19273 ⋅161591.

It can be written as a sum of positive squares in 2 ways, for example, as 1418501569 + 2014932544 = 37663^2 + 44888^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3433434113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3433434133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6197258 + ... + 6197811.

It is an arithmetic number, because the mean of its divisors is an integer number (861457365).

Almost surely, 2^3433434113 is an apocalyptic number.

It is an amenable number.

3433434113 is a deficient number, since it is larger than the sum of its proper divisors (12395347).

3433434113 is a wasteful number, since it uses less digits than its factorization.

3433434113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12395346.

The product of its digits is 15552, while the sum is 29.

The square root of 3433434113 is about 58595.5127377515. The cubic root of 3433434113 is about 1508.6074193761.

Adding to 3433434113 its reverse (3114343343), we get a palindrome (6547777456).

The spelling of 3433434113 in words is "three billion, four hundred thirty-three million, four hundred thirty-four thousand, one hundred thirteen".