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343351100413 is a prime number
BaseRepresentation
bin1001111111100010101…
…00100000001111111101
31012211020201200002210201
410333301110200033331
521111140340203123
6421422221403501
733543363125236
oct4776124401775
91184221602721
10343351100413
11122683821712
1256663709591
13264bb245709
14128927cc08d
158de848e5ad
hex4ff15203fd

343351100413 has 2 divisors, whose sum is σ = 343351100414. Its totient is φ = 343351100412.

The previous prime is 343351100377. The next prime is 343351100453. The reversal of 343351100413 is 314001153343.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 342339669604 + 1011430809 = 585098^2 + 31803^2 .

It is a cyclic number.

It is not a de Polignac number, because 343351100413 - 29 = 343351099901 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (343351100453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171675550206 + 171675550207.

It is an arithmetic number, because the mean of its divisors is an integer number (171675550207).

Almost surely, 2343351100413 is an apocalyptic number.

It is an amenable number.

343351100413 is a deficient number, since it is larger than the sum of its proper divisors (1).

343351100413 is an equidigital number, since it uses as much as digits as its factorization.

343351100413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 343351100413 its reverse (314001153343), we get a palindrome (657352253756).

The spelling of 343351100413 in words is "three hundred forty-three billion, three hundred fifty-one million, one hundred thousand, four hundred thirteen".