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34341140117 is a prime number
BaseRepresentation
bin11111111110111001…
…000011011010010101
310021122021220200002102
4133332321003122111
51030312312440432
623435345451445
72324001606014
oct377671033225
9107567820072
1034341140117
1113622750939
1267a4940b85
13331388a06b
14193ac00a7b
15d5ecd7962
hex7fee43695

34341140117 has 2 divisors, whose sum is σ = 34341140118. Its totient is φ = 34341140116.

The previous prime is 34341140107. The next prime is 34341140149. The reversal of 34341140117 is 71104114343.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31707500356 + 2633639761 = 178066^2 + 51319^2 .

It is an emirp because it is prime and its reverse (71104114343) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34341140117 - 212 = 34341136021 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 34341140117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34341140107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17170570058 + 17170570059.

It is an arithmetic number, because the mean of its divisors is an integer number (17170570059).

Almost surely, 234341140117 is an apocalyptic number.

It is an amenable number.

34341140117 is a deficient number, since it is larger than the sum of its proper divisors (1).

34341140117 is an equidigital number, since it uses as much as digits as its factorization.

34341140117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4032, while the sum is 29.

The spelling of 34341140117 in words is "thirty-four billion, three hundred forty-one million, one hundred forty thousand, one hundred seventeen".