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343413024545 = 568682604909
BaseRepresentation
bin1001111111101010000…
…00101110011100100001
31012211102001012011202002
410333311000232130201
521111302213241140
6421432312533345
733545044355123
oct4776500563441
91184361164662
10343413024545
11122705777188
12566803b1255
13264cb017406
141289ab0b213
158dedb22415
hex4ff502e721

343413024545 has 4 divisors (see below), whose sum is σ = 412095629460. Its totient is φ = 274730419632.

The previous prime is 343413024497. The next prime is 343413024599. The reversal of 343413024545 is 545420314343.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 74184872161 + 269228152384 = 272369^2 + 518872^2 .

It is a cyclic number.

It is not a de Polignac number, because 343413024545 - 26 = 343413024481 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 343413024499 and 343413024508.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34341302450 + ... + 34341302459.

It is an arithmetic number, because the mean of its divisors is an integer number (103023907365).

Almost surely, 2343413024545 is an apocalyptic number.

It is an amenable number.

343413024545 is a deficient number, since it is larger than the sum of its proper divisors (68682604915).

343413024545 is an equidigital number, since it uses as much as digits as its factorization.

343413024545 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 68682604914.

The product of its (nonzero) digits is 345600, while the sum is 38.

Adding to 343413024545 its reverse (545420314343), we get a palindrome (888833338888).

The spelling of 343413024545 in words is "three hundred forty-three billion, four hundred thirteen million, twenty-four thousand, five hundred forty-five".

Divisors: 1 5 68682604909 343413024545