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34342213333 = 136711251203
BaseRepresentation
bin11111111110111101…
…001001011011010101
310021122100221012021011
4133332331021123111
51030313101311313
623435424452221
72324013665641
oct377675113325
9107570835234
1034342213333
111362331419a
1267a517a071
133313b746bc
14193adddc21
15d5ee4a93d
hex7fef496d5

34342213333 has 4 divisors (see below), whose sum is σ = 34342601248. Its totient is φ = 34341825420.

The previous prime is 34342213331. The next prime is 34342213351. The reversal of 34342213333 is 33331224343.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 34342213333 - 21 = 34342213331 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 34342213295 and 34342213304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (34342213331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11110 + ... + 262312.

It is an arithmetic number, because the mean of its divisors is an integer number (8585650312).

Almost surely, 234342213333 is an apocalyptic number.

It is an amenable number.

34342213333 is a deficient number, since it is larger than the sum of its proper divisors (387915).

34342213333 is a wasteful number, since it uses less digits than its factorization.

34342213333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 387914.

The product of its digits is 46656, while the sum is 31.

Adding to 34342213333 its reverse (33331224343), we get a palindrome (67673437676).

The spelling of 34342213333 in words is "thirty-four billion, three hundred forty-two million, two hundred thirteen thousand, three hundred thirty-three".

Divisors: 1 136711 251203 34342213333