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34342314133 is a prime number
BaseRepresentation
bin11111111110111101…
…100010000010010101
310021122101010022112111
4133332331202002111
51030313113023013
623435430551021
72324014565551
oct377675420225
9107571108474
1034342314133
11136233829a6
1267a5208471
133313bab54a
14193b028861
15d5ee6a73d
hex7fef62095

34342314133 has 2 divisors, whose sum is σ = 34342314134. Its totient is φ = 34342314132.

The previous prime is 34342314109. The next prime is 34342314137. The reversal of 34342314133 is 33141324343.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18176971684 + 16165342449 = 134822^2 + 127143^2 .

It is a cyclic number.

It is not a de Polignac number, because 34342314133 - 25 = 34342314101 is a prime.

It is a super-3 number, since 3×343423141333 (a number of 33 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 34342314095 and 34342314104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34342314137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17171157066 + 17171157067.

It is an arithmetic number, because the mean of its divisors is an integer number (17171157067).

Almost surely, 234342314133 is an apocalyptic number.

It is an amenable number.

34342314133 is a deficient number, since it is larger than the sum of its proper divisors (1).

34342314133 is an equidigital number, since it uses as much as digits as its factorization.

34342314133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 31104, while the sum is 31.

Adding to 34342314133 its reverse (33141324343), we get a palindrome (67483638476).

The spelling of 34342314133 in words is "thirty-four billion, three hundred forty-two million, three hundred fourteen thousand, one hundred thirty-three".