Base | Representation |
---|---|
bin | 1111100111011111111001… |
… | …00010100110000100110111 |
3 | 11111121002222220102111022022 |
4 | 13303233330202212010313 |
5 | 14000131420104140212 |
6 | 201012421002423355 |
7 | 10143110114305112 |
oct | 763577442460467 |
9 | 144532886374268 |
10 | 34342500458807 |
11 | aa40633224742 |
12 | 3a27981b01b5b |
13 | 162163a179058 |
14 | 86a286129579 |
15 | 3e84d96e6772 |
hex | 1f3bfc8a6137 |
34342500458807 has 2 divisors, whose sum is σ = 34342500458808. Its totient is φ = 34342500458806.
The previous prime is 34342500458797. The next prime is 34342500458813. The reversal of 34342500458807 is 70885400524343.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 34342500458807 - 28 = 34342500458551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34342500458207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17171250229403 + 17171250229404.
It is an arithmetic number, because the mean of its divisors is an integer number (17171250229404).
Almost surely, 234342500458807 is an apocalyptic number.
34342500458807 is a deficient number, since it is larger than the sum of its proper divisors (1).
34342500458807 is an equidigital number, since it uses as much as digits as its factorization.
34342500458807 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12902400, while the sum is 53.
The spelling of 34342500458807 in words is "thirty-four trillion, three hundred forty-two billion, five hundred million, four hundred fifty-eight thousand, eight hundred seven".
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