Base | Representation |
---|---|
bin | 1111100111011111111001… |
… | …00010110110000000001111 |
3 | 11111121002222220112210210121 |
4 | 13303233330202312000033 |
5 | 14000131420113232142 |
6 | 201012421004045411 |
7 | 10143110114666242 |
oct | 763577442660017 |
9 | 144532886483717 |
10 | 34342500524047 |
11 | aa40633269761 |
12 | 3a27981b33867 |
13 | 162163a19c961 |
14 | 86a286145259 |
15 | 3e84d970ac67 |
hex | 1f3bfc8b600f |
34342500524047 has 2 divisors, whose sum is σ = 34342500524048. Its totient is φ = 34342500524046.
The previous prime is 34342500524021. The next prime is 34342500524069. The reversal of 34342500524047 is 74042500524343.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-34342500524047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 34342500523994 and 34342500524012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34342500524147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17171250262023 + 17171250262024.
It is an arithmetic number, because the mean of its divisors is an integer number (17171250262024).
Almost surely, 234342500524047 is an apocalyptic number.
34342500524047 is a deficient number, since it is larger than the sum of its proper divisors (1).
34342500524047 is an equidigital number, since it uses as much as digits as its factorization.
34342500524047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1612800, while the sum is 43.
The spelling of 34342500524047 in words is "thirty-four trillion, three hundred forty-two billion, five hundred million, five hundred twenty-four thousand, forty-seven".
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