Base | Representation |
---|---|
bin | 110001111110100010100… |
… | …110001000001110011011 |
3 | 110011022210201020211211021 |
4 | 301332202212020032123 |
5 | 422232131113224114 |
6 | 11145424504143311 |
7 | 503061541623421 |
oct | 61764246101633 |
9 | 13138721224737 |
10 | 3434406773659 |
11 | 11045840a8404 |
12 | 47573ba67b37 |
13 | 1bbb2b4c84c4 |
14 | bc3248a3111 |
15 | 5e50ba8c024 |
hex | 31fa298839b |
3434406773659 has 2 divisors, whose sum is σ = 3434406773660. Its totient is φ = 3434406773658.
The previous prime is 3434406773657. The next prime is 3434406773683. The reversal of 3434406773659 is 9563776044343.
3434406773659 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3434406773659 - 21 = 3434406773657 is a prime.
Together with 3434406773657, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 3434406773597 and 3434406773606.
It is not a weakly prime, because it can be changed into another prime (3434406773653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1717203386829 + 1717203386830.
It is an arithmetic number, because the mean of its divisors is an integer number (1717203386830).
Almost surely, 23434406773659 is an apocalyptic number.
3434406773659 is a deficient number, since it is larger than the sum of its proper divisors (1).
3434406773659 is an equidigital number, since it uses as much as digits as its factorization.
3434406773659 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 137168640, while the sum is 61.
The spelling of 3434406773659 in words is "three trillion, four hundred thirty-four billion, four hundred six million, seven hundred seventy-three thousand, six hundred fifty-nine".
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