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34345020433 = 53996361367
BaseRepresentation
bin11111111111000111…
…110110110000010001
310021122120012210212211
4133333013312300101
51030314311123213
623440004552121
72324046566623
oct377707666021
9107576183784
1034345020433
1113624961209
1267a60b2641
1333146182c9
14193b530c13
15d6030253d
hex7ff1f6c11

34345020433 has 4 divisors (see below), whose sum is σ = 34351387200. Its totient is φ = 34338653668.

The previous prime is 34345020419. The next prime is 34345020443. The reversal of 34345020433 is 33402054343.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33402054343 = 74771722049.

It is a cyclic number.

It is not a de Polignac number, because 34345020433 - 25 = 34345020401 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 34345020395 and 34345020404.

It is not an unprimeable number, because it can be changed into a prime (34345020443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3175285 + ... + 3186082.

It is an arithmetic number, because the mean of its divisors is an integer number (8587846800).

Almost surely, 234345020433 is an apocalyptic number.

It is an amenable number.

34345020433 is a deficient number, since it is larger than the sum of its proper divisors (6366767).

34345020433 is an equidigital number, since it uses as much as digits as its factorization.

34345020433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6366766.

The product of its (nonzero) digits is 51840, while the sum is 31.

Adding to 34345020433 its reverse (33402054343), we get a palindrome (67747074776).

The spelling of 34345020433 in words is "thirty-four billion, three hundred forty-five million, twenty thousand, four hundred thirty-three".

Divisors: 1 5399 6361367 34345020433