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34352311325243 is a prime number
BaseRepresentation
bin1111100111110010001010…
…10100000101001000111011
311111122001022122022010221212
413303321011110011020323
514000312013144401433
6201021122311353335
710143605204301212
oct763710524051073
9144561278263855
1034352311325243
11aa448081a891a
123a2985b68284b
131622541915272
1486a9370d8079
153e88b0b94d48
hex1f3e4550523b

34352311325243 has 2 divisors, whose sum is σ = 34352311325244. Its totient is φ = 34352311325242.

The previous prime is 34352311325219. The next prime is 34352311325249. The reversal of 34352311325243 is 34252311325343.

It is a strong prime.

It is an emirp because it is prime and its reverse (34252311325343) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34352311325243 - 26 = 34352311325179 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 34352311325243.

It is not a weakly prime, because it can be changed into another prime (34352311325249) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17176155662621 + 17176155662622.

It is an arithmetic number, because the mean of its divisors is an integer number (17176155662622).

Almost surely, 234352311325243 is an apocalyptic number.

34352311325243 is a deficient number, since it is larger than the sum of its proper divisors (1).

34352311325243 is an equidigital number, since it uses as much as digits as its factorization.

34352311325243 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 777600, while the sum is 41.

The spelling of 34352311325243 in words is "thirty-four trillion, three hundred fifty-two billion, three hundred eleven million, three hundred twenty-five thousand, two hundred forty-three".