Base | Representation |
---|---|
bin | 11111111111101101… |
… | …111110000010101001 |
3 | 10021200021000102101201 |
4 | 133333231332002221 |
5 | 1030324340334003 |
6 | 23441003044201 |
7 | 2324230532056 |
oct | 377755760251 |
9 | 107607012351 |
10 | 34355011753 |
11 | 1362a5658a7 |
12 | 67a9510661 |
13 | 3316705c2a |
14 | 193c9b202d |
15 | d61127b1d |
hex | 7ffb7e0a9 |
34355011753 has 2 divisors, whose sum is σ = 34355011754. Its totient is φ = 34355011752.
The previous prime is 34355011729. The next prime is 34355011777. The reversal of 34355011753 is 35711055343.
It is a balanced prime because it is at equal distance from previous prime (34355011729) and next prime (34355011777).
It can be written as a sum of positive squares in only one way, i.e., 33770677824 + 584333929 = 183768^2 + 24173^2 .
It is an emirp because it is prime and its reverse (35711055343) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-34355011753 is a prime.
It is not a weakly prime, because it can be changed into another prime (34355014753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17177505876 + 17177505877.
It is an arithmetic number, because the mean of its divisors is an integer number (17177505877).
Almost surely, 234355011753 is an apocalyptic number.
It is an amenable number.
34355011753 is a deficient number, since it is larger than the sum of its proper divisors (1).
34355011753 is an equidigital number, since it uses as much as digits as its factorization.
34355011753 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 94500, while the sum is 37.
The spelling of 34355011753 in words is "thirty-four billion, three hundred fifty-five million, eleven thousand, seven hundred fifty-three".
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