3440012113 has 4 divisors (see below), whose sum is σ = 3440514100. Its totient is φ = 3439510128.

The previous prime is 3440012039. The next prime is 3440012119. The reversal of 3440012113 is 3112100443.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1133803584 + 2306208529 = 33672^2 + 48023^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3440012113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3440012119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 240570 + ... + 254467.

It is an arithmetic number, because the mean of its divisors is an integer number (860128525).

Almost surely, 2^3440012113 is an apocalyptic number.

It is an amenable number.

3440012113 is a deficient number, since it is larger than the sum of its proper divisors (501987).

3440012113 is an equidigital number, since it uses as much as digits as its factorization.

3440012113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 501986.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 3440012113 is about 58651.6164568377. The cubic root of 3440012113 is about 1509.5702346968.

Adding to 3440012113 its reverse (3112100443), we get a palindrome (6552112556).

The spelling of 3440012113 in words is "three billion, four hundred forty million, twelve thousand, one hundred thirteen".