Base | Representation |
---|---|
bin | 110010000011110111110… |
… | …110101010110011010011 |
3 | 110011212120201112121021111 |
4 | 302003313312222303103 |
5 | 422330342311441433 |
6 | 11152212550434151 |
7 | 503353452502321 |
oct | 62036766526323 |
9 | 13155521477244 |
10 | 3440132140243 |
11 | 1106a51a00027 |
12 | 476879362957 |
13 | 1bc531708496 |
14 | bc709022d11 |
15 | 5e744526dcd |
hex | 320f7daacd3 |
3440132140243 has 2 divisors, whose sum is σ = 3440132140244. Its totient is φ = 3440132140242.
The previous prime is 3440132140241. The next prime is 3440132140331. The reversal of 3440132140243 is 3420412310443.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3440132140243 - 21 = 3440132140241 is a prime.
Together with 3440132140241, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (3440132140241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1720066070121 + 1720066070122.
It is an arithmetic number, because the mean of its divisors is an integer number (1720066070122).
Almost surely, 23440132140243 is an apocalyptic number.
3440132140243 is a deficient number, since it is larger than the sum of its proper divisors (1).
3440132140243 is an equidigital number, since it uses as much as digits as its factorization.
3440132140243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 3440132140243 its reverse (3420412310443), we get a palindrome (6860544450686).
The spelling of 3440132140243 in words is "three trillion, four hundred forty billion, one hundred thirty-two million, one hundred forty thousand, two hundred forty-three".
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