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34401331969 is a prime number
BaseRepresentation
bin100000000010011110…
…101010101100000001
310021210111011201210021
4200002132222230001
51030423220110334
623445335533441
72325332332324
oct400236525401
9107714151707
1034401331969
1113653722974
126800b2a281
1333231a3444
141944bcc7bb
15d652273b4
hex8027aab01

34401331969 has 2 divisors, whose sum is σ = 34401331970. Its totient is φ = 34401331968.

The previous prime is 34401331963. The next prime is 34401332029. The reversal of 34401331969 is 96913310443.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 33092339569 + 1308992400 = 181913^2 + 36180^2 .

It is an emirp because it is prime and its reverse (96913310443) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34401331969 - 29 = 34401331457 is a prime.

It is a super-2 number, since 2×344013319692 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (34401331963) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17200665984 + 17200665985.

It is an arithmetic number, because the mean of its divisors is an integer number (17200665985).

Almost surely, 234401331969 is an apocalyptic number.

It is an amenable number.

34401331969 is a deficient number, since it is larger than the sum of its proper divisors (1).

34401331969 is an equidigital number, since it uses as much as digits as its factorization.

34401331969 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 209952, while the sum is 43.

The spelling of 34401331969 in words is "thirty-four billion, four hundred one million, three hundred thirty-one thousand, nine hundred sixty-nine".