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34402000111 is a prime number
BaseRepresentation
bin100000000010100001…
…001101110011101111
310021210112102200022021
4200002201031303233
51030423403000421
623445402131011
72325341114263
oct400241156357
9107715380267
1034402000111
1113654039956
1268011b0a67
1333233785ab
141944d240a3
15d6530a341
hex80284dcef

34402000111 has 2 divisors, whose sum is σ = 34402000112. Its totient is φ = 34402000110.

The previous prime is 34402000099. The next prime is 34402000117. The reversal of 34402000111 is 11100020443.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 34402000111 - 25 = 34402000079 is a prime.

It is a super-2 number, since 2×344020001112 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34402000117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17201000055 + 17201000056.

It is an arithmetic number, because the mean of its divisors is an integer number (17201000056).

Almost surely, 234402000111 is an apocalyptic number.

34402000111 is a deficient number, since it is larger than the sum of its proper divisors (1).

34402000111 is an equidigital number, since it uses as much as digits as its factorization.

34402000111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 34402000111 its reverse (11100020443), we get a palindrome (45502020554).

The spelling of 34402000111 in words is "thirty-four billion, four hundred two million, one hundred eleven", and thus it is an aban number.