Base | Representation |
---|---|
bin | 100000000010100001… |
… | …001101110011101111 |
3 | 10021210112102200022021 |
4 | 200002201031303233 |
5 | 1030423403000421 |
6 | 23445402131011 |
7 | 2325341114263 |
oct | 400241156357 |
9 | 107715380267 |
10 | 34402000111 |
11 | 13654039956 |
12 | 68011b0a67 |
13 | 33233785ab |
14 | 1944d240a3 |
15 | d6530a341 |
hex | 80284dcef |
34402000111 has 2 divisors, whose sum is σ = 34402000112. Its totient is φ = 34402000110.
The previous prime is 34402000099. The next prime is 34402000117. The reversal of 34402000111 is 11100020443.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 34402000111 - 25 = 34402000079 is a prime.
It is a super-2 number, since 2×344020001112 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34402000117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17201000055 + 17201000056.
It is an arithmetic number, because the mean of its divisors is an integer number (17201000056).
Almost surely, 234402000111 is an apocalyptic number.
34402000111 is a deficient number, since it is larger than the sum of its proper divisors (1).
34402000111 is an equidigital number, since it uses as much as digits as its factorization.
34402000111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 34402000111 its reverse (11100020443), we get a palindrome (45502020554).
The spelling of 34402000111 in words is "thirty-four billion, four hundred two million, one hundred eleven", and thus it is an aban number.
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •