Base | Representation |
---|---|
bin | 100000000010100001… |
… | …001101110100000101 |
3 | 10021210112102200100002 |
4 | 200002201031310011 |
5 | 1030423403001013 |
6 | 23445402131045 |
7 | 2325341114324 |
oct | 400241156405 |
9 | 107715380302 |
10 | 34402000133 |
11 | 13654039976 |
12 | 68011b0a85 |
13 | 33233785c7 |
14 | 1944d240bb |
15 | d6530a358 |
hex | 80284dd05 |
34402000133 has 2 divisors, whose sum is σ = 34402000134. Its totient is φ = 34402000132.
The previous prime is 34402000117. The next prime is 34402000159. The reversal of 34402000133 is 33100020443.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 24580595524 + 9821404609 = 156782^2 + 99103^2 .
It is a cyclic number.
It is not a de Polignac number, because 34402000133 - 24 = 34402000117 is a prime.
It is a super-2 number, since 2×344020001332 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34402000183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17201000066 + 17201000067.
It is an arithmetic number, because the mean of its divisors is an integer number (17201000067).
Almost surely, 234402000133 is an apocalyptic number.
It is an amenable number.
34402000133 is a deficient number, since it is larger than the sum of its proper divisors (1).
34402000133 is an equidigital number, since it uses as much as digits as its factorization.
34402000133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 20.
Adding to 34402000133 its reverse (33100020443), we get a palindrome (67502020576).
The spelling of 34402000133 in words is "thirty-four billion, four hundred two million, one hundred thirty-three", and thus it is an aban number.
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