Base | Representation |
---|---|
bin | 1010000000110010111… |
… | …11101001101110000111 |
3 | 1012212222200221102002202 |
4 | 11000121133221232013 |
5 | 21114030412031211 |
6 | 422013140025115 |
7 | 33566156125031 |
oct | 5003137515607 |
9 | 1185880842082 |
10 | 344025111431 |
11 | 12299a230111 |
12 | 5681139219b |
13 | 26597a856c1 |
14 | 1291811cc51 |
15 | 8e3772b53b |
hex | 50197e9b87 |
344025111431 has 2 divisors, whose sum is σ = 344025111432. Its totient is φ = 344025111430.
The previous prime is 344025111383. The next prime is 344025111461. The reversal of 344025111431 is 134111520443.
It is a strong prime.
It is an emirp because it is prime and its reverse (134111520443) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 344025111431 - 214 = 344025095047 is a prime.
It is a super-2 number, since 2×3440251114312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 344025111394 and 344025111403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (344025111461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172012555715 + 172012555716.
It is an arithmetic number, because the mean of its divisors is an integer number (172012555716).
Almost surely, 2344025111431 is an apocalyptic number.
344025111431 is a deficient number, since it is larger than the sum of its proper divisors (1).
344025111431 is an equidigital number, since it uses as much as digits as its factorization.
344025111431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 344025111431 its reverse (134111520443), we get a palindrome (478136631874).
The spelling of 344025111431 in words is "three hundred forty-four billion, twenty-five million, one hundred eleven thousand, four hundred thirty-one".
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