Base | Representation |
---|---|
bin | 100000000010100011… |
… | …001011000011101101 |
3 | 10021210120101202001002 |
4 | 200002203023003231 |
5 | 1030424020410013 |
6 | 23445421130045 |
7 | 2325345352052 |
oct | 400243130355 |
9 | 107716352032 |
10 | 34402513133 |
11 | 1365435a33a |
12 | 68013b9925 |
13 | 33234c7c61 |
14 | 1945019029 |
15 | d653ac358 |
hex | 8028cb0ed |
34402513133 has 2 divisors, whose sum is σ = 34402513134. Its totient is φ = 34402513132.
The previous prime is 34402513111. The next prime is 34402513139. The reversal of 34402513133 is 33131520443.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 26186359684 + 8216153449 = 161822^2 + 90643^2 .
It is a cyclic number.
It is not a de Polignac number, because 34402513133 - 230 = 33328771309 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 34402513096 and 34402513105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34402513139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17201256566 + 17201256567.
It is an arithmetic number, because the mean of its divisors is an integer number (17201256567).
Almost surely, 234402513133 is an apocalyptic number.
It is an amenable number.
34402513133 is a deficient number, since it is larger than the sum of its proper divisors (1).
34402513133 is an equidigital number, since it uses as much as digits as its factorization.
34402513133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 29.
The spelling of 34402513133 in words is "thirty-four billion, four hundred two million, five hundred thirteen thousand, one hundred thirty-three".
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