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34403042433 = 311467680811
BaseRepresentation
bin100000000010100101…
…001100010010000001
310021210121101122002210
4200002211030102001
51030424134324213
623445440332333
72325353015154
oct400245142201
9107717348083
1034403042433
1113654690a81
1268016140a9
133323651b56
141945115c9b
15d654640c3
hex80294c481

34403042433 has 4 divisors (see below), whose sum is σ = 45870723248. Its totient is φ = 22935361620.

The previous prime is 34403042353. The next prime is 34403042447. The reversal of 34403042433 is 33424030443.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 34403042433 - 225 = 34369488001 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 34403042433.

It is not an unprimeable number, because it can be changed into a prime (34403042473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5733840403 + ... + 5733840408.

It is an arithmetic number, because the mean of its divisors is an integer number (11467680812).

Almost surely, 234403042433 is an apocalyptic number.

It is an amenable number.

34403042433 is a deficient number, since it is larger than the sum of its proper divisors (11467680815).

34403042433 is a wasteful number, since it uses less digits than its factorization.

34403042433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11467680814.

The product of its (nonzero) digits is 41472, while the sum is 30.

Adding to 34403042433 its reverse (33424030443), we get a palindrome (67827072876).

The spelling of 34403042433 in words is "thirty-four billion, four hundred three million, forty-two thousand, four hundred thirty-three".

Divisors: 1 3 11467680811 34403042433