Base | Representation |
---|---|
bin | 110010000100000111110… |
… | …100011110101111010011 |
3 | 110011220021101120101112102 |
4 | 302010013310132233103 |
5 | 422331414400031003 |
6 | 11152255315551015 |
7 | 503363214336356 |
oct | 62040764365723 |
9 | 13156241511472 |
10 | 3440400002003 |
11 | 110707a123588 |
12 | 476932bbb46b |
13 | 1bc575062c73 |
14 | bc73282c29d |
15 | 5e75ccd8588 |
hex | 32107d1ebd3 |
3440400002003 has 2 divisors, whose sum is σ = 3440400002004. Its totient is φ = 3440400002002.
The previous prime is 3440400001999. The next prime is 3440400002119. The reversal of 3440400002003 is 3002000040443.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (3002000040443) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3440400002003 - 22 = 3440400001999 is a prime.
It is not a weakly prime, because it can be changed into another prime (3440400002203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1720200001001 + 1720200001002.
It is an arithmetic number, because the mean of its divisors is an integer number (1720200001002).
Almost surely, 23440400002003 is an apocalyptic number.
3440400002003 is a deficient number, since it is larger than the sum of its proper divisors (1).
3440400002003 is an equidigital number, since it uses as much as digits as its factorization.
3440400002003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 20.
Adding to 3440400002003 its reverse (3002000040443), we get a palindrome (6442400042446).
The spelling of 3440400002003 in words is "three trillion, four hundred forty billion, four hundred million, two thousand, three".
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