Base | Representation |
---|---|
bin | 110010000100101101000… |
… | …001010001001100101011 |
3 | 110011221212212221102200101 |
4 | 302010231001101030223 |
5 | 422334204133031103 |
6 | 11152441252450231 |
7 | 503414533231324 |
oct | 62045501211453 |
9 | 13157785842611 |
10 | 3441024111403 |
11 | 110736a44917a |
12 | 476a88019977 |
13 | 1bc644450578 |
14 | bc79168d44b |
15 | 5e7979b9a1d |
hex | 3212d05132b |
3441024111403 has 2 divisors, whose sum is σ = 3441024111404. Its totient is φ = 3441024111402.
The previous prime is 3441024111377. The next prime is 3441024111419. The reversal of 3441024111403 is 3041114201443.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3441024111403 - 221 = 3441022014251 is a prime.
It is not a weakly prime, because it can be changed into another prime (3441024111803) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1720512055701 + 1720512055702.
It is an arithmetic number, because the mean of its divisors is an integer number (1720512055702).
Almost surely, 23441024111403 is an apocalyptic number.
3441024111403 is a deficient number, since it is larger than the sum of its proper divisors (1).
3441024111403 is an equidigital number, since it uses as much as digits as its factorization.
3441024111403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 3441024111403 its reverse (3041114201443), we get a palindrome (6482138312846).
The spelling of 3441024111403 in words is "three trillion, four hundred forty-one billion, twenty-four million, one hundred eleven thousand, four hundred three".
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