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34411432001 = 139247564259
BaseRepresentation
bin100000000011000101…
…001100100001000001
310021211012011212102112
4200003011030201001
51030433311311001
623450340225105
72325514226432
oct400305144101
9107735155375
1034411432001
11136593a1201
12680439b195
1333252cb6ab
14194629b489
15d6606ecbb
hex80314c841

34411432001 has 4 divisors (see below), whose sum is σ = 34658996400. Its totient is φ = 34163867604.

The previous prime is 34411431961. The next prime is 34411432039. The reversal of 34411432001 is 10023411443.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10023411443 = 31323335853.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-34411432001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (34411432901) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 123781991 + ... + 123782268.

It is an arithmetic number, because the mean of its divisors is an integer number (8664749100).

Almost surely, 234411432001 is an apocalyptic number.

It is an amenable number.

34411432001 is a deficient number, since it is larger than the sum of its proper divisors (247564399).

34411432001 is a wasteful number, since it uses less digits than its factorization.

34411432001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 247564398.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 34411432001 its reverse (10023411443), we get a palindrome (44434843444).

The spelling of 34411432001 in words is "thirty-four billion, four hundred eleven million, four hundred thirty-two thousand, one".

Divisors: 1 139 247564259 34411432001