Base | Representation |
---|---|
bin | 1111101001100101010011… |
… | …10000100000101110110011 |
3 | 11111211221212121121010011010 |
4 | 13310302221300200232303 |
5 | 14002320112231321120 |
6 | 201105344203322003 |
7 | 10151224060566345 |
oct | 764625160405663 |
9 | 144757777533133 |
10 | 34414126042035 |
11 | aa68a48a81523 |
12 | 3a39831220303 |
13 | 1628313315c6c |
14 | 86d91c9b5295 |
15 | 3ea2cc8ab7e0 |
hex | 1f4ca9c20bb3 |
34414126042035 has 16 divisors (see below), whose sum is σ = 55212636013056. Its totient is φ = 18304189107168.
The previous prime is 34414126042027. The next prime is 34414126042097. The reversal of 34414126042035 is 53024062141443.
It is not a de Polignac number, because 34414126042035 - 23 = 34414126042027 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 34414126041984 and 34414126042002.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3125709849 + ... + 3125720858.
It is an arithmetic number, because the mean of its divisors is an integer number (3450789750816).
Almost surely, 234414126042035 is an apocalyptic number.
34414126042035 is a deficient number, since it is larger than the sum of its proper divisors (20798509971021).
34414126042035 is a wasteful number, since it uses less digits than its factorization.
34414126042035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6251431082.
The product of its (nonzero) digits is 276480, while the sum is 39.
Adding to 34414126042035 its reverse (53024062141443), we get a palindrome (87438188183478).
The spelling of 34414126042035 in words is "thirty-four trillion, four hundred fourteen billion, one hundred twenty-six million, forty-two thousand, thirty-five".
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