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344230434133 is a prime number
BaseRepresentation
bin1010000001001011011…
…10111001010101010101
31012220112000021212220021
411000211232321111111
521114440442343013
6422045352505141
733604231261345
oct5004556712525
91186460255807
10344230434133
11122a951190a3
125686a0ab1b1
13265cb484621
14129374c8d25
158e4a787a8d
hex5025bb9555

344230434133 has 2 divisors, whose sum is σ = 344230434134. Its totient is φ = 344230434132.

The previous prime is 344230434059. The next prime is 344230434151. The reversal of 344230434133 is 331434032443.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 310224492484 + 34005941649 = 556978^2 + 184407^2 .

It is an emirp because it is prime and its reverse (331434032443) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 344230434133 - 221 = 344228336981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (344230434433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172115217066 + 172115217067.

It is an arithmetic number, because the mean of its divisors is an integer number (172115217067).

Almost surely, 2344230434133 is an apocalyptic number.

It is an amenable number.

344230434133 is a deficient number, since it is larger than the sum of its proper divisors (1).

344230434133 is an equidigital number, since it uses as much as digits as its factorization.

344230434133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 124416, while the sum is 34.

Adding to 344230434133 its reverse (331434032443), we get a palindrome (675664466576).

The spelling of 344230434133 in words is "three hundred forty-four billion, two hundred thirty million, four hundred thirty-four thousand, one hundred thirty-three".