Base | Representation |
---|---|
bin | 100000000100000101… |
… | …001101011110011111 |
3 | 10021212100202102211121 |
4 | 200010011031132133 |
5 | 1031002110310101 |
6 | 23452140031411 |
7 | 2326106661163 |
oct | 400405153637 |
9 | 107770672747 |
10 | 34428213151 |
11 | 13667913122 |
12 | 6809b32567 |
13 | 3328925977 |
14 | 19485c8ca3 |
15 | d677870a1 |
hex | 80414d79f |
34428213151 has 4 divisors (see below), whose sum is σ = 35538800704. Its totient is φ = 33317625600.
The previous prime is 34428213143. The next prime is 34428213163. The reversal of 34428213151 is 15131282443.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15131282443 = 1163 ⋅13010561.
It is a cyclic number.
It is not a de Polignac number, because 34428213151 - 23 = 34428213143 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (34428213101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 555293730 + ... + 555293791.
It is an arithmetic number, because the mean of its divisors is an integer number (8884700176).
Almost surely, 234428213151 is an apocalyptic number.
34428213151 is a gapful number since it is divisible by the number (31) formed by its first and last digit.
34428213151 is a deficient number, since it is larger than the sum of its proper divisors (1110587553).
34428213151 is a wasteful number, since it uses less digits than its factorization.
34428213151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1110587552.
The product of its digits is 23040, while the sum is 34.
Adding to 34428213151 its reverse (15131282443), we get a palindrome (49559495594).
The spelling of 34428213151 in words is "thirty-four billion, four hundred twenty-eight million, two hundred thirteen thousand, one hundred fifty-one".
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