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344310131401 = 595835764939
BaseRepresentation
bin1010000001010100111…
…10111010101011001001
31012220201120020220222221
411000222132322223021
521120121343201101
6422101321014041
733606216554035
oct5005236725311
91186646226887
10344310131401
11123026102905
1256890924321
1326611b39c82
1412943d131c5
158e5277baa1
hex502a7baac9

344310131401 has 4 divisors (see below), whose sum is σ = 350145896400. Its totient is φ = 338474366404.

The previous prime is 344310131393. The next prime is 344310131411. The reversal of 344310131401 is 104131013443.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 344310131401 - 23 = 344310131393 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (344310131411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2917882411 + ... + 2917882528.

It is an arithmetic number, because the mean of its divisors is an integer number (87536474100).

Almost surely, 2344310131401 is an apocalyptic number.

It is an amenable number.

344310131401 is a deficient number, since it is larger than the sum of its proper divisors (5835764999).

344310131401 is an equidigital number, since it uses as much as digits as its factorization.

344310131401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5835764998.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 344310131401 its reverse (104131013443), we get a palindrome (448441144844).

The spelling of 344310131401 in words is "three hundred forty-four billion, three hundred ten million, one hundred thirty-one thousand, four hundred one".

Divisors: 1 59 5835764939 344310131401