Base | Representation |
---|---|
bin | 100000000100010001… |
… | …010111110001010001 |
3 | 10021212120202101210121 |
4 | 200010101113301101 |
5 | 1031003414313131 |
6 | 23452332230241 |
7 | 2326146036262 |
oct | 400421276121 |
9 | 107776671717 |
10 | 34431401041 |
11 | 136696a0244 |
12 | 680b00b381 |
13 | 33294a09ab |
14 | 1948bb8969 |
15 | d67bb6911 |
hex | 804457c51 |
34431401041 has 4 divisors (see below), whose sum is σ = 34765686592. Its totient is φ = 34097115492.
The previous prime is 34431401033. The next prime is 34431401063. The reversal of 34431401041 is 14010413443.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 34431401041 - 23 = 34431401033 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 34431400997 and 34431401015.
It is not an unprimeable number, because it can be changed into a prime (34431401941) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 167142621 + ... + 167142826.
It is an arithmetic number, because the mean of its divisors is an integer number (8691421648).
Almost surely, 234431401041 is an apocalyptic number.
It is an amenable number.
34431401041 is a deficient number, since it is larger than the sum of its proper divisors (334285551).
34431401041 is a wasteful number, since it uses less digits than its factorization.
34431401041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 334285550.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 34431401041 its reverse (14010413443), we get a palindrome (48441814484).
The spelling of 34431401041 in words is "thirty-four billion, four hundred thirty-one million, four hundred one thousand, forty-one".
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