Base | Representation |
---|---|
bin | 110010000110101111111… |
… | …110111101000101101011 |
3 | 110012011120000101012022011 |
4 | 302012233332331011223 |
5 | 422403204124220133 |
6 | 11153443302340351 |
7 | 503523143213401 |
oct | 62065776750553 |
9 | 13164500335264 |
10 | 3443221320043 |
11 | 110829774158a |
12 | 47739ba2a6b7 |
13 | 1bc90471551b |
14 | bc91d401471 |
15 | 5e8758346cd |
hex | 321affbd16b |
3443221320043 has 2 divisors, whose sum is σ = 3443221320044. Its totient is φ = 3443221320042.
The previous prime is 3443221320031. The next prime is 3443221320059. The reversal of 3443221320043 is 3400231223443.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3443221320043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3443221319987 and 3443221320014.
It is not a weakly prime, because it can be changed into another prime (3543221320043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1721610660021 + 1721610660022.
It is an arithmetic number, because the mean of its divisors is an integer number (1721610660022).
Almost surely, 23443221320043 is an apocalyptic number.
3443221320043 is a deficient number, since it is larger than the sum of its proper divisors (1).
3443221320043 is an equidigital number, since it uses as much as digits as its factorization.
3443221320043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 3443221320043 its reverse (3400231223443), we get a palindrome (6843452543486).
The spelling of 3443221320043 in words is "three trillion, four hundred forty-three billion, two hundred twenty-one million, three hundred twenty thousand, forty-three".
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