Base | Representation |
---|---|
bin | 1010000001010111011… |
… | …11010010101011010011 |
3 | 1012220210000220101101011 |
4 | 11000223233102223103 |
5 | 21120142241414420 |
6 | 422103352351351 |
7 | 33606563630110 |
oct | 5005357225323 |
9 | 1186700811334 |
10 | 344331201235 |
11 | 123036a9399a |
12 | 568979a5557 |
13 | 26616306328 |
14 | 12946a39907 |
15 | 8e5453e95a |
hex | 502bbd2ad3 |
344331201235 has 16 divisors (see below), whose sum is σ = 472342239936. Its totient is φ = 236054527488.
The previous prime is 344331201229. The next prime is 344331201281. The reversal of 344331201235 is 532102133443.
It is a happy number.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-344331201235 is a prime.
It is a super-2 number, since 2×3443312012352 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 344331201197 and 344331201206.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1070482 + ... + 1354471.
It is an arithmetic number, because the mean of its divisors is an integer number (29521389996).
Almost surely, 2344331201235 is an apocalyptic number.
344331201235 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
344331201235 is a deficient number, since it is larger than the sum of its proper divisors (128011038701).
344331201235 is a wasteful number, since it uses less digits than its factorization.
344331201235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2429022.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 344331201235 its reverse (532102133443), we get a palindrome (876433334678).
The spelling of 344331201235 in words is "three hundred forty-four billion, three hundred thirty-one million, two hundred one thousand, two hundred thirty-five".
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