Base | Representation |
---|---|
bin | 110010000111101100111… |
… | …001100011010110111111 |
3 | 110012021012020102212121022 |
4 | 302013230321203112333 |
5 | 422412302242022421 |
6 | 11154132531254355 |
7 | 503560363060055 |
oct | 62075471432677 |
9 | 13167166385538 |
10 | 3444243314111 |
11 | 1108771617886 |
12 | 47762614a3bb |
13 | 1bca38383642 |
14 | bc9b90361d5 |
15 | 5e8d540c7ab |
hex | 321ece635bf |
3444243314111 has 2 divisors, whose sum is σ = 3444243314112. Its totient is φ = 3444243314110.
The previous prime is 3444243314087. The next prime is 3444243314191. The reversal of 3444243314111 is 1114133424443.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3444243314111 - 218 = 3444243051967 is a prime.
It is a super-2 number, since 2×34442433141112 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3444243314191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1722121657055 + 1722121657056.
It is an arithmetic number, because the mean of its divisors is an integer number (1722121657056).
Almost surely, 23444243314111 is an apocalyptic number.
3444243314111 is a deficient number, since it is larger than the sum of its proper divisors (1).
3444243314111 is an equidigital number, since it uses as much as digits as its factorization.
3444243314111 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 55296, while the sum is 35.
Adding to 3444243314111 its reverse (1114133424443), we get a palindrome (4558376738554).
The spelling of 3444243314111 in words is "three trillion, four hundred forty-four billion, two hundred forty-three million, three hundred fourteen thousand, one hundred eleven".
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