Base | Representation |
---|---|
bin | 1010000001100100100… |
… | …10100010011010110011 |
3 | 1012221001200201000200211 |
4 | 11000302102202122303 |
5 | 21120403410312201 |
6 | 422122320124551 |
7 | 33612400035352 |
oct | 5006222423263 |
9 | 1187050630624 |
10 | 344441104051 |
11 | 123093029570 |
12 | 56908766757 |
13 | 26633006395 |
14 | 12957487999 |
15 | 8e5deed651 |
hex | 50324a26b3 |
344441104051 has 4 divisors (see below), whose sum is σ = 375753931704. Its totient is φ = 313128276400.
The previous prime is 344441104039. The next prime is 344441104057. The reversal of 344441104051 is 150401144443.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 150401144443 = 11 ⋅13672831313.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-344441104051 is a prime.
It is a super-2 number, since 2×3444411040512 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (344441104057) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15656413810 + ... + 15656413831.
It is an arithmetic number, because the mean of its divisors is an integer number (93938482926).
Almost surely, 2344441104051 is an apocalyptic number.
344441104051 is a deficient number, since it is larger than the sum of its proper divisors (31312827653).
344441104051 is a wasteful number, since it uses less digits than its factorization.
344441104051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31312827652.
The product of its (nonzero) digits is 15360, while the sum is 31.
Adding to 344441104051 its reverse (150401144443), we get a palindrome (494842248494).
The spelling of 344441104051 in words is "three hundred forty-four billion, four hundred forty-one million, one hundred four thousand, fifty-one".
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