34450121455403 has 4 divisors (see below), whose sum is σ = 34450151054088. Its totient is φ = 34450091856720.

The previous prime is 34450121455391. The next prime is 34450121455433. The reversal of 34450121455403 is 30455412105443.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 34450121455403 - 2¹² = 34450121451307 is a prime.

It is a super-3 number, since 3×34450121455403³ (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (34450121455433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12978833 + ... + 15406178.

It is an arithmetic number, because the mean of its divisors is an integer number (8612537763522).

Almost surely, 2^{34450121455403} is an apocalyptic number.

34450121455403 is a deficient number, since it is larger than the sum of its proper divisors (29598685).

34450121455403 is a wasteful number, since it uses less digits than its factorization.

34450121455403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29598684.

The product of its (nonzero) digits is 576000, while the sum is 41.

The spelling of 34450121455403 in words is "thirty-four trillion, four hundred fifty billion, one hundred twenty-one million, four hundred fifty-five thousand, four hundred three".