3445154013541 has 4 divisors (see below), whose sum is σ = 3445801239232. Its totient is φ = 3444506787852.

The previous prime is 3445154013479. The next prime is 3445154013571. The reversal of 3445154013541 is 1453104515443.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3445154013541 - 2¹¹ = 3445154011493 is a prime.

It is a super-2 number, since 2×3445154013541² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3445154013494 and 3445154013503.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3445154013571) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 323604861 + ... + 323615506.

It is an arithmetic number, because the mean of its divisors is an integer number (861450309808).

Almost surely, 2^{3445154013541} is an apocalyptic number.

It is an amenable number.

3445154013541 is a deficient number, since it is larger than the sum of its proper divisors (647225691).

3445154013541 is an equidigital number, since it uses as much as digits as its factorization.

3445154013541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 647225690.

The product of its (nonzero) digits is 288000, while the sum is 40.

Adding to 3445154013541 its reverse (1453104515443), we get a palindrome (4898258528984).

The spelling of 3445154013541 in words is "three trillion, four hundred forty-five billion, one hundred fifty-four million, thirteen thousand, five hundred forty-one".