Base | Representation |
---|---|
bin | 1111101011101001100100… |
… | …01011101000110010001011 |
3 | 11112002202011022012221111011 |
4 | 13311310302023220302023 |
5 | 14010001023342043034 |
6 | 201202130233344351 |
7 | 10156316530232131 |
oct | 765646213506213 |
9 | 145082138187434 |
10 | 34485134331019 |
11 | aa96077338a79 |
12 | 3a4b5498680b7 |
13 | 1631c1b6105c8 |
14 | 873137495751 |
15 | 3ec086789864 |
hex | 1f5d322e8c8b |
34485134331019 has 2 divisors, whose sum is σ = 34485134331020. Its totient is φ = 34485134331018.
The previous prime is 34485134331017. The next prime is 34485134331097. The reversal of 34485134331019 is 91013343158443.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 34485134331019 - 21 = 34485134331017 is a prime.
It is a super-2 number, since 2×344851343310192 (a number of 28 digits) contains 22 as substring.
Together with 34485134331017, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (34485134331017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17242567165509 + 17242567165510.
It is an arithmetic number, because the mean of its divisors is an integer number (17242567165510).
Almost surely, 234485134331019 is an apocalyptic number.
34485134331019 is a deficient number, since it is larger than the sum of its proper divisors (1).
34485134331019 is an equidigital number, since it uses as much as digits as its factorization.
34485134331019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1866240, while the sum is 49.
The spelling of 34485134331019 in words is "thirty-four trillion, four hundred eighty-five billion, one hundred thirty-four million, three hundred thirty-one thousand, nineteen".
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