Base | Representation |
---|---|
bin | 1010000010100000010… |
… | …10111101001101101101 |
3 | 1012222100122001011220121 |
4 | 11001100022331031231 |
5 | 21122420230330013 |
6 | 422244145244541 |
7 | 33630665206234 |
oct | 5012012751555 |
9 | 1188318034817 |
10 | 344942433133 |
11 | 123320013521 |
12 | 56a28633751 |
13 | 266b2b353cc |
14 | 129a3ca7b1b |
15 | 8e8d02a58d |
hex | 50502bd36d |
344942433133 has 2 divisors, whose sum is σ = 344942433134. Its totient is φ = 344942433132.
The previous prime is 344942433089. The next prime is 344942433151. The reversal of 344942433133 is 331334249443.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 344942433124 + 9 = 587318^2 + 3^2 .
It is a cyclic number.
It is not a de Polignac number, because 344942433133 - 213 = 344942424941 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 344942433133.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (344942433533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172471216566 + 172471216567.
It is an arithmetic number, because the mean of its divisors is an integer number (172471216567).
Almost surely, 2344942433133 is an apocalyptic number.
It is an amenable number.
344942433133 is a deficient number, since it is larger than the sum of its proper divisors (1).
344942433133 is an equidigital number, since it uses as much as digits as its factorization.
344942433133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1119744, while the sum is 43.
The spelling of 344942433133 in words is "three hundred forty-four billion, nine hundred forty-two million, four hundred thirty-three thousand, one hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •