Base | Representation |
---|---|
bin | 110010001100100010011… |
… | …101110111110011010011 |
3 | 110012202121012021012002021 |
4 | 302030202131313303103 |
5 | 423003421332313041 |
6 | 11200352142032311 |
7 | 504133156452145 |
oct | 62144235676323 |
9 | 13182535235067 |
10 | 3449436994771 |
11 | 110a997290a49 |
12 | 478635578697 |
13 | 1c0385396071 |
14 | bcd4cb12c95 |
15 | 5eadb370cd1 |
hex | 32322777cd3 |
3449436994771 has 2 divisors, whose sum is σ = 3449436994772. Its totient is φ = 3449436994770.
The previous prime is 3449436994673. The next prime is 3449436994807. The reversal of 3449436994771 is 1774996349443.
3449436994771 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3449436994771 - 221 = 3449434897619 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3449436994771.
It is not a weakly prime, because it can be changed into another prime (3449436994271) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1724718497385 + 1724718497386.
It is an arithmetic number, because the mean of its divisors is an integer number (1724718497386).
Almost surely, 23449436994771 is an apocalyptic number.
3449436994771 is a deficient number, since it is larger than the sum of its proper divisors (1).
3449436994771 is an equidigital number, since it uses as much as digits as its factorization.
3449436994771 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 493807104, while the sum is 70.
The spelling of 3449436994771 in words is "three trillion, four hundred forty-nine billion, four hundred thirty-six million, nine hundred ninety-four thousand, seven hundred seventy-one".
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