Base | Representation |
---|---|
bin | 110010001101001011001… |
… | …011010101011000010011 |
3 | 110012211100210110111112212 |
4 | 302031023023111120103 |
5 | 423011321210013133 |
6 | 11200544021142335 |
7 | 504156122065112 |
oct | 62151313253023 |
9 | 13184323414485 |
10 | 3450120001043 |
11 | 1110207883741 |
12 | 4787a625a9ab |
13 | 1c0463a354a1 |
14 | bcdb5705c79 |
15 | 5eb2b2d8148 |
hex | 3234b2d5613 |
3450120001043 has 2 divisors, whose sum is σ = 3450120001044. Its totient is φ = 3450120001042.
The previous prime is 3450120001037. The next prime is 3450120001057. The reversal of 3450120001043 is 3401000210543.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3450120001043 is a prime.
It is not a weakly prime, because it can be changed into another prime (3450120001343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1725060000521 + 1725060000522.
It is an arithmetic number, because the mean of its divisors is an integer number (1725060000522).
Almost surely, 23450120001043 is an apocalyptic number.
3450120001043 is a deficient number, since it is larger than the sum of its proper divisors (1).
3450120001043 is an equidigital number, since it uses as much as digits as its factorization.
3450120001043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 3450120001043 its reverse (3401000210543), we get a palindrome (6851120211586).
The spelling of 3450120001043 in words is "three trillion, four hundred fifty billion, one hundred twenty million, one thousand, forty-three".
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